
{"id":337,"date":"2016-09-28T00:02:08","date_gmt":"2016-09-28T00:02:08","guid":{"rendered":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/?p=337"},"modified":"2016-09-28T02:16:15","modified_gmt":"2016-09-28T02:16:15","slug":"week-5","status":"publish","type":"post","link":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/2016\/09\/28\/week-5\/","title":{"rendered":"Week 5"},"content":{"rendered":"<p><strong>Coupled Simple Harmonic Oscillators<\/strong><\/p>\n<p>In this week, we begin to address systems with two degrees of freedom. \u00a0We first looked at a\u00a0<strong>demonstration<\/strong> where there are two 1kg masses suspended from strings of about 50cm each in length. \u00a0The masses are then connected to each other through a spring with a small spring constant (called <img src='https:\/\/s0.wp.com\/latex.php?latex=k_c&#038;bg=T&#038;fg=000000&#038;s=0' alt='k_c' title='k_c' class='latex' \/>, for example). \u00a0 In the demonstration we did the following:<\/p>\n<ol>\n<li>First we displaced only one of the masses from equilibrium, and set the system in motion. \u00a0As with the Wilberforce pendulum, energy &#8220;sloshed&#8221; from one of the degrees of freedom to the other in manner reminiscent of &#8220;beats&#8221; that we saw while superposing waves of nearly the same frequency.<\/li>\n<li>Next, we displaced both masses by an equal amount in the same direction, such that the spring connecting the two masses was not stretched or compressed. \u00a0After letting it go, the system just oscillated back and forth, with the spring never being compressed.<\/li>\n<li>Finally, we displaced each mass by an equal amount, but in the opposite direction. \u00a0This time the masses again just moved back and forth in an antisymmetric manner, somewhat similar to #2.<\/li>\n<\/ol>\n<p>Clearly the phenomena associated with two degrees of freedom is very rich, exhibiting beats, and having two special types of excitations. \u00a0How do these appear in the mathematics?<\/p>\n<p>First, we must write down Newton&#8217;s 2nd law for each of the masses:<\/p>\n<img src='https:\/\/s0.wp.com\/latex.php?latex=%5Coverrightarrow%7BF%7D_A+%3D+-m+%5Comega_0%5E2+x_A+-+k_c+%28x_A+-x_B%29+%3D+m+%5Cddot%7Bx%7D_A&#038;bg=T&#038;fg=000000&#038;s=0' alt='\\overrightarrow{F}_A = -m \\omega_0^2 x_A - k_c (x_A -x_B) = m \\ddot{x}_A' title='\\overrightarrow{F}_A = -m \\omega_0^2 x_A - k_c (x_A -x_B) = m \\ddot{x}_A' class='latex' \/>\n<p>&nbsp;<\/p>\n<img src='https:\/\/s0.wp.com\/latex.php?latex=%5Coverrightarrow%7BF%7D_B+%3D+-m+%5Comega_0%5E2+x_B+-+k_c+%28x_B+-x_A%29+%3D+m+%5Cddot%7Bx%7D_B&#038;bg=T&#038;fg=000000&#038;s=0' alt='\\overrightarrow{F}_B = -m \\omega_0^2 x_B - k_c (x_B -x_A) = m \\ddot{x}_B' title='\\overrightarrow{F}_B = -m \\omega_0^2 x_B - k_c (x_B -x_A) = m \\ddot{x}_B' class='latex' \/>\n<p>The most important aspect of these equations are that they are\u00a0<strong>coupled<\/strong> equations. \u00a0That is, the equation for <img src='https:\/\/s0.wp.com\/latex.php?latex=x_A&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_A' title='x_A' class='latex' \/> depends on <img src='https:\/\/s0.wp.com\/latex.php?latex=x_B&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_B' title='x_B' class='latex' \/> and vice-versa. \u00a0The two degrees of freedom &#8220;talk to each other&#8221; through the coupling spring. \u00a0Indeed, if the coupling spring constant is taken down to zero, the communication is lost, and the two degrees of freedom become uncoupled.<\/p>\n<p>It is not obvious at this point how to approach finding the solutions to this equation, but you can check that if you add (and subtract) the two equations from each other you get equations that look exactly like the original (uncoupled) SHO equations:<\/p>\n<img src='https:\/\/s0.wp.com\/latex.php?latex=%5Cddot%7Bx%7D_%2B+%3D+-+%5Comega_0%5E2+x_%2B&#038;bg=T&#038;fg=000000&#038;s=0' alt='\\ddot{x}_+ = - \\omega_0^2 x_+' title='\\ddot{x}_+ = - \\omega_0^2 x_+' class='latex' \/>\n<p><img src='https:\/\/s0.wp.com\/latex.php?latex=%5Cddot%7Bx%7D_-+%3D+-+%28%5Comega_0%5E2+%2B+2+k_c%2Fm%29+x_-&#038;bg=T&#038;fg=000000&#038;s=0' alt='\\ddot{x}_- = - (\\omega_0^2 + 2 k_c\/m) x_-' title='\\ddot{x}_- = - (\\omega_0^2 + 2 k_c\/m) x_-' class='latex' \/>.<\/p>\n<p>Here we have defined <img src='https:\/\/s0.wp.com\/latex.php?latex=x_%2B+%3D+x_A+%2B+x_B&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_+ = x_A + x_B' title='x_+ = x_A + x_B' class='latex' \/> and <img src='https:\/\/s0.wp.com\/latex.php?latex=x_-+%3D+x_A+-+x_B&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_- = x_A - x_B' title='x_- = x_A - x_B' class='latex' \/>.<\/p>\n<p>We know these equations! \u00a0So we know their solutions! \u00a0We have:<\/p>\n<img src='https:\/\/s0.wp.com\/latex.php?latex=x_%2B+%28t%29+%3D+A_%2B+%5Ccos%28%5Comega_%2B+t+%2B+%5Calpha_%2B+%29&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_+ (t) = A_+ \\cos(\\omega_+ t + \\alpha_+ )' title='x_+ (t) = A_+ \\cos(\\omega_+ t + \\alpha_+ )' class='latex' \/>\n<p><img src='https:\/\/s0.wp.com\/latex.php?latex=x_-%28t%29+%3D+A_-+%5Ccos%28%5Comega_-+t+%2B+%5Calpha_-+%29&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_-(t) = A_- \\cos(\\omega_- t + \\alpha_- )' title='x_-(t) = A_- \\cos(\\omega_- t + \\alpha_- )' class='latex' \/>.<\/p>\n<p>There are now 4 coefficients that are determined only after inputting a particular initial condition for the positions and velocities of the two masses.<\/p>\n<p>These solutions can now be used to get back the results for <img src='https:\/\/s0.wp.com\/latex.php?latex=x_A+%5Ctext%7B+and+%7D+x_B&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_A \\text{ and } x_B' title='x_A \\text{ and } x_B' class='latex' \/>:<\/p>\n<img src='https:\/\/s0.wp.com\/latex.php?latex=x_A+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Cleft%5B+A_%2B+%5Ccos+%28%5Comega_%2B+t+%2B+%5Calpha_%2B+%29+%2B+A_-+%5Ccos+%28%5Comega_-+t+%2B+%5Calpha_-+%29+%5Cright%5D&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_A = \\frac{1}{2} \\left[ A_+ \\cos (\\omega_+ t + \\alpha_+ ) + A_- \\cos (\\omega_- t + \\alpha_- ) \\right]' title='x_A = \\frac{1}{2} \\left[ A_+ \\cos (\\omega_+ t + \\alpha_+ ) + A_- \\cos (\\omega_- t + \\alpha_- ) \\right]' class='latex' \/>\n<img src='https:\/\/s0.wp.com\/latex.php?latex=x_B+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Cleft%5B+A_%2B+%5Ccos+%28%5Comega_%2B+t+%2B+%5Calpha_%2B+%29+-+A_-+%5Ccos+%28%5Comega_-+t+%2B+%5Calpha_-+%29+%5Cright%5D&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_B = \\frac{1}{2} \\left[ A_+ \\cos (\\omega_+ t + \\alpha_+ ) - A_- \\cos (\\omega_- t + \\alpha_- ) \\right]' title='x_B = \\frac{1}{2} \\left[ A_+ \\cos (\\omega_+ t + \\alpha_+ ) - A_- \\cos (\\omega_- t + \\alpha_- ) \\right]' class='latex' \/>\n<p>To explore this solution, let&#8217;s consider a particular initial condition where at t=0, we have <img src='https:\/\/s0.wp.com\/latex.php?latex=x_A+%3D+A&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_A = A' title='x_A = A' class='latex' \/> and <img src='https:\/\/s0.wp.com\/latex.php?latex=x_B+%3D+0&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_B = 0' title='x_B = 0' class='latex' \/> and both velocities are zero. \u00a0This corresponds to <img src='https:\/\/s0.wp.com\/latex.php?latex=%5Calpha_%2B+%3D+%5Calpha_-+%3D+0&#038;bg=T&#038;fg=000000&#038;s=0' alt='\\alpha_+ = \\alpha_- = 0' title='\\alpha_+ = \\alpha_- = 0' class='latex' \/> and <img src='https:\/\/s0.wp.com\/latex.php?latex=A_%2B+%3D+A_-+%3D+A&#038;bg=T&#038;fg=000000&#038;s=0' alt='A_+ = A_- = A' title='A_+ = A_- = A' class='latex' \/>. \u00a0Then we have<\/p>\n<img src='https:\/\/s0.wp.com\/latex.php?latex=x_A+%3D+%5Cfrac%7BA%7D%7B2%7D+%5Cleft%5B+%5Ccos+%28%5Comega_%2B+t%29+%2B+%5Ccos%28%5Comega_-+t%29+%5Cright%5D&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_A = \\frac{A}{2} \\left[ \\cos (\\omega_+ t) + \\cos(\\omega_- t) \\right]' title='x_A = \\frac{A}{2} \\left[ \\cos (\\omega_+ t) + \\cos(\\omega_- t) \\right]' class='latex' \/>\n<p>&nbsp;<\/p>\n<img src='https:\/\/s0.wp.com\/latex.php?latex=x_B+%3D+%5Cfrac%7BA%7D%7B2%7D+%5Cleft%5B+%5Ccos+%28%5Comega_%2B+t%29+-+%5Ccos%28%5Comega_-+t%29+%5Cright%5D&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_B = \\frac{A}{2} \\left[ \\cos (\\omega_+ t) - \\cos(\\omega_- t) \\right]' title='x_B = \\frac{A}{2} \\left[ \\cos (\\omega_+ t) - \\cos(\\omega_- t) \\right]' class='latex' \/>\n<p>Superposing these gives the beat formula! \u00a0Using <img src='https:\/\/s0.wp.com\/latex.php?latex=%5Cbar%7B%5Comega%7D+%3D+%5Cfrac%7B%5Comega_%2B+%2B+%5Comega_-%7D%7B2%7D&#038;bg=T&#038;fg=000000&#038;s=0' alt='\\bar{\\omega} = \\frac{\\omega_+ + \\omega_-}{2}' title='\\bar{\\omega} = \\frac{\\omega_+ + \\omega_-}{2}' class='latex' \/> and\u00a0<img src='https:\/\/s0.wp.com\/latex.php?latex=%5CDelta%7B%5Comega%7D+%3D+%5Cfrac%7B%5Comega_-+-+%5Comega_%2B%7D%7B2%7D&#038;bg=T&#038;fg=000000&#038;s=0' alt='\\Delta{\\omega} = \\frac{\\omega_- - \\omega_+}{2}' title='\\Delta{\\omega} = \\frac{\\omega_- - \\omega_+}{2}' class='latex' \/>, we have:<\/p>\n<img src='https:\/\/s0.wp.com\/latex.php?latex=x_A+%3D+A+%5Ccos%28%5Cbar%7B%5Comega%7D+t%29+%5Ccos%5Cleft%28+%5Cfrac%7B%5CDelta+%5Comega%7D%7B2%7D+t+%5Cright%29&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_A = A \\cos(\\bar{\\omega} t) \\cos\\left( \\frac{\\Delta \\omega}{2} t \\right)' title='x_A = A \\cos(\\bar{\\omega} t) \\cos\\left( \\frac{\\Delta \\omega}{2} t \\right)' class='latex' \/>\n<p>&nbsp;<\/p>\n<img src='https:\/\/s0.wp.com\/latex.php?latex=x_B+%3D+A+%5Csin%28%5Cbar%7B%5Comega%7D+t%29+%5Csin%5Cleft%28+%5Cfrac%7B%5CDelta+%5Comega%7D%7B2%7D+t+%5Cright%29&#038;bg=T&#038;fg=000000&#038;s=0' alt='x_B = A \\sin(\\bar{\\omega} t) \\sin\\left( \\frac{\\Delta \\omega}{2} t \\right)' title='x_B = A \\sin(\\bar{\\omega} t) \\sin\\left( \\frac{\\Delta \\omega}{2} t \\right)' class='latex' \/>\n<p>So we see that, in the equations, the motion\/energy &#8220;slosh&#8221; between the two degrees of freedom. \u00a0Here is the mathematica notebook that you can use to explore the behavior of this very interesting system!<\/p>\n<p><a href=\"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-content\/uploads\/sites\/5\/2016\/09\/Week-5.nb\">https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-content\/uploads\/sites\/5\/2016\/09\/Week-5.nb<\/a><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Coupled Simple Harmonic Oscillators In this week, we begin to address systems with two degrees of freedom. \u00a0We first looked at a\u00a0demonstration where there are two 1kg masses suspended from strings of about 50cm each in length. \u00a0The masses are &hellip; <a href=\"https:\/\/jhubisz.expressions.syr.edu\/phy360\/2016\/09\/28\/week-5\/\">Continue reading <span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"_links":{"self":[{"href":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-json\/wp\/v2\/posts\/337"}],"collection":[{"href":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-json\/wp\/v2\/comments?post=337"}],"version-history":[{"count":24,"href":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-json\/wp\/v2\/posts\/337\/revisions"}],"predecessor-version":[{"id":362,"href":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-json\/wp\/v2\/posts\/337\/revisions\/362"}],"wp:attachment":[{"href":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-json\/wp\/v2\/media?parent=337"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-json\/wp\/v2\/categories?post=337"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/jhubisz.expressions.syr.edu\/phy360\/wp-json\/wp\/v2\/tags?post=337"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}